Câu hỏi 26

Ta có \(z\left( 1+i \right)=3-5i\Leftrightarrow z=\frac{3-5i}{1+i}=\frac{\left( 3-5i \right)\left( 1-i \right)}{1-{{i}^{2}}}=-1-4i\Rightarrow \left| z \right|=\sqrt{{{\left( -1 \right)}^{2}}+{{\left( -4 \right)}^{2}}}=\sqrt{17}.\)

Chọn A