Câu hỏi 24

\(\mathop {\lim }\limits_{x \to 0} f\left( x \right) = \mathop {\lim }\limits_{x \to 0} {{1 - \root 3 \of {1 - x} } \over x} = \mathop {\lim }\limits_{x \to 0} {{1 - \left( {1 - x} \right)} \over {x\left( {1 + \root 3 \of {1 - x}  + {{\root 3 \of {1 - x} }^2}} \right)}} = \mathop {\lim }\limits_{x \to 0} {1 \over {1 + \root 3 \of {1 - x}  + {{\root 3 \of {1 - x} }^2}}} = {1 \over {1 + 1 + 1}} = {1 \over 3}\)

Chọn B.