Câu hỏi 30

\(\mathop {\lim }\limits_{x \to  - \infty } \left( {{x^3} - 4{x^5} + 2x + 1} \right) = \mathop {\lim }\limits_{x \to  - \infty } {x^5}\left( { - 4 + \dfrac{1}{{{x^2}}} + \dfrac{2}{{{x^4}}} + \dfrac{1}{{{x^5}}}} \right) =  + \infty \).

Chọn A.