Câu hỏi 37

\(\left\{ \begin{array}{l}\mathop {\lim }\limits_{x \to {3^ + }} \left( {4x - 3} \right) = 4.3 - 3 = 9\\\mathop {\lim }\limits_{x \to {3^ + }} \left( {x - 3} \right) = 0\\x \to {3^ + } \Rightarrow x - 3 > 0\end{array} \right. \Rightarrow \mathop {\lim }\limits_{x \to {3^ + }} \dfrac{{4x - 3}}{{x - 3}} =  + \infty \).

Chọn D.