Câu hỏi 4

\(\begin{gathered}
\underbrace {CuO,F{e_2}{O_3},FeO}_{m\,gam} + \left\{ \begin{gathered}
{H_2}S{O_4}_{}:0,1mol \hfill \\
HCl:\,0,1\,mol \hfill \\
\end{gathered} \right.\xrightarrow{{}}muoi\, + {H_2}O \hfill \\
\underbrace {CuO,F{e_2}{O_3},FeO}_{m\,gam} + \left\{ \begin{gathered}
{H_2} \hfill \\
CO \hfill \\
\end{gathered} \right.\xrightarrow{{}}KL\, + \left\{ \begin{gathered}
{H_2}O \hfill \\
C{O_2} \hfill \\
\end{gathered} \right. \hfill \\
\end{gathered} \)

∑ n_H+ = 2n_H2SO4 + n_HCl =  0,1.2 + 0,1 = 0,3 (mol)

=> n_{O (Trong oxit)} = 1/ 2 n_H+ = 0,15 (mol)

∑ n_{CO + H2} = n_{O (Trong oxit)} = 0,15 (mol) => V = 0,15.22,4 = 3,36 (lít)

Đáp án A