Câu hỏi 13

NO: x mol

CO₂: y mol

x+y=0,2

30x+44y=0,2.37

=>x=0,1 mol; y=0,1 mol

=>n_MgCO3=n_CO2=0,1 mol

\(\begin{gathered}
\left\{ \begin{gathered}
Mg:a \hfill \\
MgO:b \hfill \\
MgC{O_3}:0,1 \hfill \\
\end{gathered} \right.\xrightarrow{{HNO3:2,15}}\left\{ \begin{gathered}
NO:0,1 \hfill \\
C{O_2}:0,1 \hfill \\
N{H_4}N{O_3}:c \hfill \\
\end{gathered} \right. \hfill \\
\left\{ \begin{gathered}
2x = 0,1.3 + 8z\,(BT\,e) \hfill \\
24x + 40y + 8,4 = 30 \hfill \\
2,15 = 0,1 + 2z + 2(x + y + 0,1)\,(BTNT\,\,\,N) \hfill \\
\end{gathered} \right. \hfill \\
= > \left\{ \begin{gathered}
x = 0,65 \hfill \\
y = 0,15 \hfill \\
z = 0,125 \hfill \\
\end{gathered} \right. = > {m_{muoi}} = {m_{Mg{{(N{O_3})}_2}}} + {m_{N{H_4}N{O_3}}} = 143,2gam \hfill \\
\end{gathered} \)

Đáp án C